On the basis of the following observations made with aqueous solutions, find the number of complexes in which the secondary valence of the metal ion is 6 Formula Moles of AgCl precipitated per mole of the compound with excess AgNO3 i PdCl2. 4NH3 2 ii NiCl2.6H2O 2 iii PtCl4⋅ 2HCl 0 iv CoCl3 . 4NH3 1 v PtCl4 ⋅ 2NH3 0

Question

On the basis of the following observations made with aqueous solutions, find the number of complexes in which the secondary valence of the metal ion is 6 Formula Moles of AgCl precipitated per mole of the compound with excess AgNO3 i PdCl2. 4NH3 2 ii NiCl2.6H2O 2 iii PtCl4⋅ 2HCl 0 iv CoCl3 . 4NH3 1 v PtCl4 ⋅ 2NH3 0 (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

The secondary valence is equal to the coordination number of the metal ion. Number of moles of AgCl indicates that the Cl- ion is not attached to the central metal ion. Formula Moles of AgCl precipitated per mole of the compound with excess AgNO3 i Pt(NH3)4Cl2 4 ii NiH2O6Cl2 6 iii PtCl4(HCl)2 6 iv CoCl3 (NH3)4Cl 6 v PtCl4 (NH3)2 6

	Formula	Moles of $A g Cl$ precipitated per mole of the compound with excess $A g N O_{3}$
i	$P d C l_{2} .4 N H_{3}$	2
ii	$N i C l_{2} .6 H_{2} O$	2
iii	$PtC l_{4} \cdot 2 H Cl$	0
iv	$C o C l_{3} .4 N H_{3}$	1
v	$PtC l_{4} \cdot 2 N H_{3}$	0