On the basis of the fact that NaNH2 can deprotonate HC≡ CH but not CH2=CH2 and the hybridization effect, order the following. four acids according to acidity undersetI mathopHC≡ CH undersetII mathopCH2=CH2 undersetIII mathopCH3-CH3 undersetIV mathopNH3

Question

On the basis of the fact that NaNH2 can deprotonate HC≡ CH but not CH2=CH2 and the hybridization effect, order the following. four acids according to acidity undersetI mathopHC≡ CH undersetII mathopCH2=CH2 undersetIII mathopCH3-CH3 undersetIV mathopNH3  (A) IV < III < II < I (B) III < 11 < IV < I (C) I < IV < II < III (D) III < IV < II < I

Tardigrade Admin · Accepted Answer

Since, NH2- can deprotonate HC≡ CH,NH3 is weaker acid than HC≡ CH. On the other hand, NH2- cannot deprotonate CH2=CH2 therefore NH3 is stronger acid than ethane. Ethane is weakest acid due to hybridisation effect.

Q. On the basis of the fact that $N a N H_{2}$ can deprotonate $H C \equiv C H$ but not $C H_{2} = C H_{2}$ and the hybridization effect, order the following. four acids according to acidity $I H C \equiv C H II C H_{2} = C H_{2} III C H_{3} - C H_{3} I V N H_{3}$

IV < III < II < I

III < 11 < IV < I

I < IV < II < III

III < IV < II < I

Since, $N H_{2}^{-}$ can deprotonate $H C \equiv C H, N H_{3}$ is weaker acid than $H C \equiv C H .$ On the other hand, $N H_{2}^{-}$ cannot deprotonate $C H_{2} = C H_{2}$ therefore $N H_{3}$ is stronger acid than ethane. Ethane is weakest acid due to hybridisation effect.

Q. On the basis of the fact that NaNH2​ can deprotonate HC≡CH but not CH2​=CH2​ and the hybridization effect, order the following. four acids according to acidity IHC≡CH​IICH2​=CH2​​IIICH3​−CH3​​IVNH3​​