On the basis of intermolecular forces predict the correct order of decreasing boiling points of the compounds:

Question

On the basis of intermolecular forces predict the correct order of decreasing boiling points of the compounds: (A) CH 3 OH > H 2> CH 4 (B) CH 3 OH > CH 4> H 2 (C) CH 4> CH 3 OH > H 2 (D) H 2> CH 4> CH 3 OH

Tardigrade Admin · Accepted Answer

Alcohol involves H-bonding; also molecular weight of CH 4> molecular weight of H 2. The greater is molecular weight of covalent compound, the higher is its bp.

Q. On the basis of intermolecular forces predict the correct order of decreasing boiling points of the compounds:

$C H_{3} O H > H_{2} > C H_{4}$

$C H_{3} O H > C H_{4} > H_{2}$

$C H_{4} > C H_{3} O H > H_{2}$

$H_{2} > C H_{4} > C H_{3} O H$

Alcohol involves $H$ -bonding; also molecular weight of $C H_{4} >$ molecular weight of $H_{2}$ . The greater is molecular weight of covalent compound, the higher is its bp.

Q. On the basis of intermolecular forces predict the correct order of decreasing boiling points of the compounds:

CH3​OH>H2​>CH4​

CH3​OH>CH4​>H2​

CH4​>CH3​OH>H2​

H2​>CH4​>CH3​OH

Alcohol involves H-bonding; also molecular weight of CH4​> molecular weight of H2​. The greater is molecular weight of covalent compound, the higher is its bp.

$C H_{3} O H > H_{2} > C H_{4}$

$C H_{3} O H > C H_{4} > H_{2}$

$C H_{4} > C H_{3} O H > H_{2}$

$H_{2} > C H_{4} > C H_{3} O H$

Alcohol involves $H$ -bonding; also molecular weight of $C H_{4} >$ molecular weight of $H_{2}$ . The greater is molecular weight of covalent compound, the higher is its bp.