Q.
On the argand plane, let α=−2+3z,β=−2−3z&∣z∣=1. Then the correct statement is -
66
159
Complex Numbers and Quadratic Equations
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Solution:
α=−2+3z α+2=3z ∣α+2∣=3∣z∣ (x+2)2+y2=9
Similarly β=−2−3z ⇒β+2=−3z ⇒∣β+2∣=∣−3z∣ (x+2)2+y2=9
Now α−β=6z⇒∣α−β∣=6∣z∣
so (α−β) moves on a circle with centre as origin and radius 6 .