Question

On treatment of ${\left[Ni{\left(N{H}_3\right)}_4\right]}^{2+}$ with concentrated $HCl$, two compounds $I$ and $II$ having the same formula, $\left[NiC{l}_2{\left(N{H}_3\right)}_2\right]$ are obtained, $I$ can be converted into $II$ by boiling with dilute $HCl$. A solution of $I$ reacts with oxalic acid to form $\left[Ni\left(C_2{O}_4\right){\left(N{H}_3\right)}_2\right]$ whereas $II$ does not react. Point out the correct statement of the following

• A. I cis, II trans; both tetrahedral
• B. I cis, II trans; both square planar
• C. I trans, II cis; both tetrahedral
• D. I trans, II cis; both sqaure planar

Answer 1

Answer: (A)

Tetrahedral complex does not show geometrical isomerism