Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
On strong heating sodium bicarbonate changes into:
Q. On strong heating sodium bicarbonate changes into:
1815
204
Manipal
Manipal 2005
Report Error
A
sodium monoxide
12%
B
sodium hydroxide
24%
C
sodium carbonate
59%
D
sodium peroxide
6%
Solution:
Sodium bicarbonate decompose on strong heating and gives sodium carbonate.
2
N
a
H
C
O
3
Δ
N
a
2
C
O
3
+
C
O
2
+
H
2
O