On six complete rotations, the screw gauge moves by 3 mm on the main scale. If there are 50 divisions on the circular scale the least count of the screw gauge is

Question

On six complete rotations, the screw gauge moves by 3 mm on the main scale. If there are 50 divisions on the circular scale the least count of the screw gauge is (A) 0.01 cm (B) 0.02 mm (C) 0.001 mm (D) 0.001 cm

Tardigrade Admin · Accepted Answer

Pitch =(3/6)=0.5 mm L.C. =(0 . 5 mm/50)=(1/100)mm=0.01 mm =0.001 cm

Q. On six complete rotations, the screw gauge moves by $3 mm$ on the main scale. If there are $50$ divisions on the circular scale the least count of the screw gauge is

$0.01 c m$

$0.02 mm$

$0.001 mm$

$0.001 c m$

Pitch $= \frac{3}{6} = 0.5 mm$
L.C. $= \frac{0.5 mm}{50} = \frac{1}{100} mm = 0.01 mm$
$= 0.001 c m$

Q. On six complete rotations, the screw gauge moves by 3mm on the main scale. If there are 50 divisions on the circular scale the least count of the screw gauge is

0.01cm

0.02mm

0.001mm

0.001cm