On passing 3 ampere of electricity for 50 minutes,1.8 g of metal deposits. The equivalent mass ofmetal is

Question

On passing 3 ampere of electricity for 50 minutes,1.8 g of metal deposits. The equivalent mass ofmetal is (A) 20.5 (B) 25.8 (C) 19.3 (D) 30.7.

Tardigrade Admin · Accepted Answer

Q = It = 3 amp × 50× 60 sec = 9000 C 9000 C of electricity deposits metal = 1.8 gm 96500 C of electricity deposits metal = (1.8/9000) × 96500 = 19.3 gm

Q. On passing 3 ampere of electricity for 50 minutes,1.8 g of metal deposits. The equivalent mass ofmetal is

20.5

25.8

19.3

30.7.

$Q = I t = 3 am p \times 50 \times 60$ sec $= 9000 C$
$9000 C$ of electricity deposits metal $= 1.8 g m$
$96500 C$ of electricity deposits metal
$= \frac{1.8}{9000} \times 96500 = 19.3 g m$

Q. On passing 3 ampere of electricity for 50 minutes,1.8 g of metal deposits. The equivalent mass ofmetal is

20.5

25.8

19.3

30.7.

Q=It=3amp×50×60 sec =9000C 9000C of electricity deposits metal =1.8gm 96500C of electricity deposits metal =90001.8​×96500=19.3gm

$Q = I t = 3 am p \times 50 \times 60$ sec $= 9000 C$
$9000 C$ of electricity deposits metal $= 1.8 g m$
$96500 C$ of electricity deposits metal
$= \frac{1.8}{9000} \times 96500 = 19.3 g m$