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  4. On passing 3 ampere of electricity for 50 minutes,1.8 g of metal deposits. The equivalent mass ofmetal is

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Q. On passing 3 ampere of electricity for 50 minutes,1.8 g of metal deposits. The equivalent mass ofmetal is

Electrochemistry

Solution:

$Q = It = 3\,amp \times 50\times 60$ sec $ = 9000\,C$
$9000\,C$ of electricity deposits metal $ = 1.8\,gm$
$ 96500\,C$ of electricity deposits metal
$ = \frac{1.8}{9000} \times 96500 = 19.3\,gm$