On moving a charge of 20 C by 2 cm, 2 J of work is done, then the potential difference between the points is

Question

On moving a charge of 20 C by 2 cm, 2 J of work is done, then the potential difference between the points is (A) 0.1 V (B) 8 V (C) 2 V (D) 0.5 V

Tardigrade Admin · Accepted Answer

Potential difference between two points in an electric field VA-VB =(W/q0) where W is work done by moving charge q0 from point A to B Here, W=2J, q0=20 c VA-VB=(2/20) =0.1 volt

Q. On moving a charge of $20 C$ by $2 c m, 2 J$ of work is done, then the potential difference between the points is

$0.1 V$

$8 V$

$2 V$

$0.5 V$

Potential difference between two points in an electric field
$V_{A} - V_{B} = \frac{W}{q _{0}}$
where $W$ is work done by moving charge $q_{0}$ from point $A$ to $B$
Here, $W = 2 J, q_{0} = 20 c$
$V_{A} - V_{B} = \frac{2}{20}$
$= 0.1$ volt

Q. On moving a charge of 20C by 2cm,2J of work is done, then the potential difference between the points is

0.1V

8V

2V

0.5V