On moving a charge of 20 C by 2 cm , 2 J of work is done. The potential difference between the points is

Question

On moving a charge of 20 C by 2 cm , 2 J of work is done. The potential difference between the points is (A)  text0.1V (B)  text8V (C)  text2V (D)  text0.5V

Tardigrade Admin · Accepted Answer

Potential difference between two points in a electric fields is, VA-VB=(W/q0) Where W is work done by moving charge q0 from point A to B . So, VA-VB=(2/20)= text0.1V (Here W=2J, q0=20C )

Q. On moving a charge of $20 C$ by $2 c m$ , $2 J$ of work is done. The potential difference between the points is

$0.1 V$

$8 V$

$2 V$

$0.5 V$

Potential difference between two points in a electric fields is,
$V_{A} - V_{B} = \frac{W}{q _{0}}$
Where $W$ is work done by moving charge $q_{0}$ from point $A$ to $B$ .
So, $V_{A} - V_{B} = \frac{2}{20} = 0.1 V$
(Here $W = 2 J, q_{0} = 20 C$ )

Q. On moving a charge of 20C by 2cm , 2J of work is done. The potential difference between the points is

0.1V

8V

2V

0.5V