Question

On moving a charge of $20 \, C$ by $2 \, cm$ , $2 \, J$ of work is done. The potential difference between the points is

• A. $\text{0.1}V$
• B. $\text{8}V$
• C. $\text{2}V$
• D. $\text{0.5}V$

Answer 1

Answer: (A)

Potential difference between two points in a electric fields is,
$V_{A}-V_{B}=\frac{W}{q_{0}}$
Where $W$ is work done by moving charge $q_{0}$ from point $A$ to $B$ .
So, $V_{A}-V_{B}=\frac{2}{20}=\text{0.1}V$
(Here $W=2J, \, q_{0}=20C$ )