On introducing a thin mica sheet of thickness 2× 10- 6 m and refractive index 1.5 in the path of one of the waves, central bright maxima shifts by n fringes. The wavelength of the wave used is 5000 overset° A , then n is

Question

On introducing a thin mica sheet of thickness 2× 10- 6 m and refractive index 1.5 in the path of one of the waves, central bright maxima shifts by n fringes. The wavelength of the wave used is 5000 overset° A , then n is (A) 1 (B) 2 (C) 5 (D) 10

Tardigrade Admin · Accepted Answer

The shift in no. of fringes is given by nλ =(μ - 1)t n=((μ - 1) t/λ )=((. 1.5 - 1 .) × 2 × (10)- 6/5000 × (10)- 10) fringes=2

Q. On introducing a thin mica sheet of thickness $2 \times 1 0^{- 6} m$ and refractive index $1.5$ in the path of one of the waves, central bright maxima shifts by $n$ fringes. The wavelength of the wave used is $5000 A^{\circ}$ , then $n$ is

$1$

$2$

$5$

$10$

The shift in no. of fringes is given by
$nλ = (μ - 1) t$
$n = \frac{( μ - 1 ) t}{λ} = \frac{( 1.5 - 1 ) \times 2 \times ( 10 ) ^{- 6}}{5000 \times ( 10 ) ^{- 10}} f r in g es = 2$

Q. On introducing a thin mica sheet of thickness 2×10−6m and refractive index 1.5 in the path of one of the waves, central bright maxima shifts by n fringes. The wavelength of the wave used is 5000A∘ , then n is

1

2

5

10

The shift in no. of fringes is given by nλ=(μ−1)t n=λ(μ−1)t​=5000×(10)−10(1.5−1)×2×(10)−6​fringes=2

Q. On introducing a thin mica sheet of thickness $2 \times 1 0^{- 6} m$ and refractive index $1.5$ in the path of one of the waves, central bright maxima shifts by $n$ fringes. The wavelength of the wave used is $5000 A^{\circ}$ , then $n$ is

$1$

$2$

$5$

$10$

The shift in no. of fringes is given by
$nλ = (μ - 1) t$
$n = \frac{( μ - 1 ) t}{λ} = \frac{( 1.5 - 1 ) \times 2 \times ( 10 ) ^{- 6}}{5000 \times ( 10 ) ^{- 10}} f r in g es = 2$