On increasing the distance between the plates of a parallel plate condenser

Question

On increasing the distance between the plates of a parallel plate condenser (A) The electric field intensity between the plates will decrease (B) The electric intensity between the plates will increase (C) The electric field intensity between the plates will remain unchanged (D) The potential difference between the plates will decrease

Tardigrade Admin · Accepted Answer

Electric field between the plates of a parallel plate capacitor, E=(σ/ε0)=(Q/A ε0) i.e., E propto do

Q. On increasing the distance between the plates of a parallel plate condenser

The electric field intensity between the plates will decrease

The electric intensity between the plates will increase

The electric field intensity between the plates will remain unchanged

The potential difference between the plates will decrease

Electric field between the plates of a parallel plate capacitor,
$E = \frac{σ}{ε _{0}} = \frac{Q}{A ε _{0}}$ i.e., $E \propto d^{o}$

Q. On increasing the distance between the plates of a parallel plate condenser

The electric field intensity between the plates will decrease

The electric intensity between the plates will increase

The electric field intensity between the plates will remain unchanged

The potential difference between the plates will decrease

Electric field between the plates of a parallel plate capacitor, E=ε0​σ​=Aε0​Q​ i.e., E∝do

Electric field between the plates of a parallel plate capacitor,
$E = \frac{σ}{ε _{0}} = \frac{Q}{A ε _{0}}$ i.e., $E \propto d^{o}$