Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
On heating K4[Fe(CN)6] with conc. H2SO4, it gives the gas
Q. On heating
K
4
[
F
e
(
CN
)
6
]
with conc.
H
2
S
O
4
,
it gives the gas
3021
225
Odisha JEE
Odisha JEE 2009
Coordination Compounds
Report Error
A
S
O
2
54%
B
C
O
2
19%
C
CO
14%
D
N
O
2
12%
Solution:
K
4
[
F
e
(
CN
)
6
]
+
6
H
2
S
O
4
+
6
H
2
O
⟶
2
K
2
S
O
4
+
F
e
S
O
4
+
3
(
N
H
4
)
2
S
O
4
+
6
CO