On Fe2O3(.s.)+(3/2)C(.s.) arrow (3/2)CO2(.g.)+2Fe(.s.);Δ H° =+234.1kJ C(.s.)+O2(.g.) arrow CO2(.g.);Δ H° =-393.5 kJ Use these equations and Δ H° values to calculate Δ H° for this reaction 4Fe(.s.)+3O2(.g.) arrow 2Fe2O3(.s.)

Question

On Fe2O3(.s.)+(3/2)C(.s.) arrow (3/2)CO2(.g.)+2Fe(.s.);Δ H° =+234.1kJ C(.s.)+O2(.g.) arrow CO2(.g.);Δ H° =-393.5 kJ Use these equations and Δ H° values to calculate Δ H° for this reaction 4Fe(.s.)+3O2(.g.) arrow 2Fe2O3(.s.) (A) -1648.7 kJ (B) -1255.3 kJ (C) -1021.2 kJ (D) -129.4 kJ

Tardigrade Admin · Accepted Answer

2Fe(.s.)+(3/2)CO2(.g.) arrow Fe2O3(.s.)+(3/2)C(.s.);Δ H° =-234.1kJ &hellip;(i) C(.s.)+O2(.g.) arrow CO2(.g.)(.Δ H° =-393.5kJ.) &hellip;(ii) Multiplying eq. (i) by 2 and eq. (ii) by 3 and on adding both equations, we get 4Fe(.s.)+3O2(.g.) arrow 2Fe2O3(.s.);Δ H° =(.-234.1× 2.)+(.-3× 393.5.) =-1648.7 kJ

Q. On Fe2​O3​(s)+23​C(s)→23​CO2​(g)+2Fe(s);ΔH∘=+234.1kJ C(s)+O2​(g)→CO2​(g);ΔH∘=−393.5 kJ Use these equations and ΔH∘ values to calculate ΔH∘ for this reaction 4Fe(s)+3O2​(g)→2Fe2​O3​(s)

-1648.7 kJ

-1255.3 kJ

-1021.2 kJ

-129.4 kJ

2Fe(s)+23​CO2​(g)→Fe2​O3​(s)+23​C(s);ΔH∘=−234.1kJ …(i) C(s)+O2​(g)→CO2​(g)(ΔH∘=−393.5kJ) …(ii) Multiplying eq. (i) by 2 and eq. (ii) by 3 and on adding both equations, we get 4Fe(s)+3O2​(g)→2Fe2​O3​(s);ΔH∘=(−234.1×2)+(−3×393.5) =−1648.7 kJ