During electrolysis of dilute H2SO4 using platinum electrodes, the oxygen gas is evolved at the anode and hydrogen is liberated at cathode.
At cathode: H++e−→21H2
At anode: 2H2O(l)→O2(g)+4e−;ΔEo=+1.23V(I) 2SO42−(aq)→S2O82−+2e−;E=+1.96V(II)
For dilute solution reaction (l) is preferred and O2 liberates at anode but at higher concentration reaction (II) is preferred.