On dissolving moderate amount of sodium metal in liquid NH3 at low temperature, which one of the following does not occur?

Question

On dissolving moderate amount of sodium metal in liquid NH3 at low temperature, which one of the following does not occur? (A) Blue coloured solution is obtained (B) Na + ions are formed in the solution (C) Liquid NH3 becomes good conductor of electricity (D) Liquid ammonia remains diamagnetic

Tardigrade Admin · Accepted Answer

The alkali metals dissolve in liquid ammonia without evolution of hydrogen. The colour of the dilute solution is blue and are paramagnetic in nature.

M \to M^{+}

(in liquid ammonia)

+ e^{-}

M + (x + y) N H_{3} \to [M (N H_{3})_{x}]^{+} +

solvated electron e^{-} (N H_{3})_{y}

Q. On dissolving moderate amount of sodium metal in liquid $N H_{3}$ at low temperature, which one of the following does not occur?

Blue coloured solution is obtained

$N a^{+}$ ions are formed in the solution

Liquid $N H_{3}$ becomes good conductor of electricity

Liquid ammonia remains diamagnetic

The alkali metals dissolve in liquid ammonia without evolution of hydrogen. The colour of the dilute solution is blue and are paramagnetic in nature.
$M \to M^{+}$ (in liquid ammonia) $+ e^{-}$
$M + (x + y) N H_{3} \to [M (N H_{3})_{x}]^{+} +$ $solvated electron e^{-} (N H_{3})_{y}$

Q. On dissolving moderate amount of sodium metal in liquid NH3​ at low temperature, which one of the following does not occur?

Blue coloured solution is obtained

Na+ ions are formed in the solution

Liquid NH3​ becomes good conductor of electricity

Liquid ammonia remains diamagnetic

The alkali metals dissolve in liquid ammonia without evolution of hydrogen. The colour of the dilute solution is blue and are paramagnetic in nature. M→M+ (in liquid ammonia) +e− M+(x+y)NH3​→[M(NH3​)x​]++ solvated electrone−(NH3​)y​​

Q. On dissolving moderate amount of sodium metal in liquid $N H_{3}$ at low temperature, which one of the following does not occur?

$N a^{+}$ ions are formed in the solution

Liquid $N H_{3}$ becomes good conductor of electricity

The alkali metals dissolve in liquid ammonia without evolution of hydrogen. The colour of the dilute solution is blue and are paramagnetic in nature.
$M \to M^{+}$ (in liquid ammonia) $+ e^{-}$
$M + (x + y) N H_{3} \to [M (N H_{3})_{x}]^{+} +$ $solvated electron e^{-} (N H_{3})_{y}$