On complete combustion of 0.492 g of an organic compound containing C , H and O, 0.7938 g of CO 2 and 0.4428 g of H 2 O was produced. The % composition of oxygen in the compound is

Question

On complete combustion of 0.492 g of an organic compound containing C , H and O, 0.7938 g of CO 2 and 0.4428 g of H 2 O was produced. The % composition of oxygen in the compound is  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

0.492 g of C x H y O z Gives 0.7938 g CO 2=0.018 moles 0.4428 g H 2 O =0.0246 moles So moles of C =0.018 ⇒ 0.216 g Moles of H =0.049 ⇒ 0.049 g ∴ wt. of Oxygen =0.492-0.216-0.049 =0.227 g % of Oxygen =(0.227/0.492) × 10046 (approx.)

Q. On complete combustion of 0.492g of an organic compound containing C,H and O, 0.7938g of CO2​ and 0.4428g of H2​O was produced. The \% composition of oxygen in the compound is ___

0.492g of Cx​Hy​Oz​ Gives 0.7938gCO2​=0.018 moles 0.4428gH2​O=0.0246 moles So moles of C=0.018⇒0.216g Moles of H=0.049⇒0.049g ∴ wt. of Oxygen =0.492−0.216−0.049 =0.227g % of Oxygen =0.4920.227​×10046 (approx.)

Q. On complete combustion of $0.492 g$ of an organic compound containing $C, H$ and $O$ , $0.7938 g$ of $C O_{2}$ and $0.4428 g$ of $H_{2} O$ was produced. The \% composition of oxygen in the compound is ___