Question

On complete combustion $0.30g$ of an organic compound gave $0.20g$ of carbon dioxide and $0.10g$ of water. The percentage of carbon in the given organic compound is ________(Nearest Integer)

Answer 1

Answer: 18

$\frac{n_{C{O}_2}}{n_{H_{2}O}}=\frac{x}{y/2}=\frac{0.2/44}{.1/18}$
$\frac{2x}{y}=\frac{36}{44}=\frac{9}{11}$
$x=\frac{9y}{22}$
$\frac{n_{C_x{H}_y{O}_2}}{n_{C{O}_2}}=\frac{1}{x}$
$\frac{0.3}{12x+y+16z}\times \frac{44}{0.2}=\frac{1}{x}$
$66x=12x+y+16z$
$54x=y+16z$
$\frac{54\times 9y}{22}-y=16z$
$\frac{464y}{22}=16z$
$z=\frac{29y}{22}$
$C_x{H}_y{O}_z=C_x{H}_y{O}_z$
$C_{\frac{9y}{22}}{H}_y{O}_{\frac{29y}{}}^{22}$
$C_9{H}_{22}{O}_{29}$ $\%$ of $C=\frac{12\times 9}{(12\times 9+22+29\times 16)}\times 100$
$=\frac{108}{594}\times 100$
$18.18\%$