On bombardment of U235 by slow neutrons, 200 MeV energy is released. If the power output of atomic reactor is 1.6 text MW, then the rate of fission will be

Question

On bombardment of U235 by slow neutrons, 200 MeV energy is released. If the power output of atomic reactor is 1.6 text MW, then the rate of fission will be (A)  5× 1016/s  (B)  10× 1016/s  (C)  15× 1016/s  (D)  20× 1016/s

Tardigrade Admin · Accepted Answer

Output power of the reactor P =1.6 MW Energy released per fission E =200 MeV ∴ E =200 × 1.6 × 10-19 MJ Thus rate of fission R=(P/E) ∴ R =(1.6/200 × 1.6 × 10-19) =5 × 1016 / s

Q. On bombardment of $U^{235}$ by slow neutrons, $200 M e V$ energy is released. If the power output of atomic reactor is $1.6 M W,$ then the rate of fission will be

$5 \times 1 0^{16} / s$

$10 \times 1 0^{16} / s$

$15 \times 1 0^{16} / s$

$20 \times 1 0^{16} / s$

Output power of the reactor $P = 1.6 M W$
Energy released per fission $E = 200 M e V$
$∴ E = 200 \times 1.6 \times 1 0^{- 19} M J$
Thus rate of fission $R = \frac{P}{E}$
$∴ R = \frac{1.6}{200 \times 1.6 \times 1 0 ^{- 19}}$
$= 5 \times 1 0^{16} / s$

Q. On bombardment of U235 by slow neutrons, 200MeV energy is released. If the power output of atomic reactor is 1.6MW, then the rate of fission will be

5×1016/s

10×1016/s

15×1016/s

20×1016/s