On bombarding U235 by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be

Question

On bombarding U235 by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be (A) 5×10 22/s (B) 5×10 16/s (C) 8×10 16/s (D) 20×10 16/s

Tardigrade Admin · Accepted Answer

Energy released on bombarding U 235 by neutron =200 MeV Power output of atomic reactor =1.6 MW ∴ Rate of fission =(1.6 × 106/200 × 106 × 1.6 × 10-19) =5 × 1016 / s

Q. On bombarding $U^{235}$ by slow neutron, $200 M e V$ energy is released. If the power output of atomic reactor is $1.6 M W$ , then the rate of fission will be

$5 \times 1 0^{22} / s$

$5 \times 1 0^{16} / s$

$8 \times 1 0^{16} / s$

$20 \times 1 0^{16} / s$

Energy released on bombarding $U^{235}$ by neutron
$= 200 M e V$
Power output of atomic reactor $= 1.6 M W$
$∴$ Rate of fission $= \frac{1.6 \times 1 0 ^{6}}{200 \times 1 0 ^{6} \times 1.6 \times 1 0 ^{- 19}}$
$= 5 \times 1 0^{16} / s$

Q. On bombarding U235 by slow neutron, 200MeV energy is released. If the power output of atomic reactor is 1.6MW, then the rate of fission will be

5×1022/s

5×1016/s

8×1016/s

20×1016/s