1. Tardigrade
  2. Question
  3. Physics
  4. On bombarding U235 by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. On bombarding $U^{235}$ by slow neutron, $200\, MeV$ energy is released. If the power output of atomic reactor is $1.6\, MW$, then the rate of fission will be

KCETKCET 2008Nuclei

Solution:

Energy released on bombarding $U ^{235}$ by neutron
$=200 \,MeV$
Power output of atomic reactor $=1.6 \,MW$
$\therefore $ Rate of fission $=\frac{1.6 \times 10^{6}}{200 \times 10^{6} \times 1.6 \times 10^{-19}}$
$=5 \times 10^{16} / s$