On being placed in water, sodium peroxide not only produces an alkaline solution but also some bubbles. If we assume that the peroxide ion picks up two protons from water to produce a compound that can be seen as the dibasic conjugate acid of peroxide ion and then this compound undergoes a redox disproportionation. Na2O2(s)+H2O(ℓ) arrow(A)+(B) (A) and (B) are

Question

On being placed in water, sodium peroxide not only produces an alkaline solution but also some bubbles. If we assume that the peroxide ion picks up two protons from water to produce a compound that can be seen as the dibasic conjugate acid of peroxide ion and then this compound undergoes a redox disproportionation. Na2O2(s)+H2O(ℓ) arrow(A)+(B) (A) and (B) are (A) H2O2 and NaOH (B) H2O and O2 (C) NaOH and O2 (D)  Na2O and NaOH

Tardigrade Admin · Accepted Answer

The reaction proceeds upsilon ia formation of H2O2 (which is dibasic conjugate acid of peroxide ion), H2O2 then disproportionates into water and oxygen. Na2O2(s)+2 H2O(ℓ) arrow 2 NaOH(a q)+H2O2(aq) H2O2(aq)arrow H2O(ℓ)+(1/2)O2(g) Thus, overall reaction is Na2O2(s)+H2O(ℓ)arrow 2 NaOH(aq)+(1/2) O2(g)

$H_{2} O_{2}$ and $N a O H$

$H_{2} O$ and $O_{2}$

$N a O H$ and $O_{2}$

$N a_{2} O$ and $N a O H$

H2​O2​ and NaOH

H2​O and O2​

NaOH and O2​

Na2​O and NaOH

$H_{2} O_{2}$ and $N a O H$

$H_{2} O$ and $O_{2}$

$N a O H$ and $O_{2}$

$N a_{2} O$ and $N a O H$