On adding excess of NH3 solution to CuSO4 solution, the dark blue colour is due to

Question

On adding excess of NH3 solution to CuSO4 solution, the dark blue colour is due to (A) [Cu(NH3)4]++ (B) [Cu(NH3)2]++ (C) [Cu(NH3)]+ (D) None of the above

Tardigrade Admin · Accepted Answer

CuSO4 + 4NH3 → [Cu(NH3)4]++ SO-- 4

Q. On adding excess of $N H_{3}$ solution to $C u S O_{4}$ solution, the dark blue colour is due to

$[C u (N H_{3})_{4}]^{++}$

$[C u (N H_{3})_{2}]^{++}$

$[C u (N H_{3})]^{+}$

None of the above

$C u S O_{4} + 4 N H_{3} \to [C u (N H_{3})_{4}]^{++} S O_{4}^{--}$

Q. On adding excess of NH3​ solution to CuSO4​ solution, the dark blue colour is due to

[Cu(NH3​)4​]++

[Cu(NH3​)2​]++

[Cu(NH3​)]+

None of the above

CuSO4​+4NH3​→[Cu(NH3​)4​]++SO4−−​

Q. On adding excess of $N H_{3}$ solution to $C u S O_{4}$ solution, the dark blue colour is due to

$[C u (N H_{3})_{4}]^{++}$

$[C u (N H_{3})_{2}]^{++}$

$[C u (N H_{3})]^{+}$

$C u S O_{4} + 4 N H_{3} \to [C u (N H_{3})_{4}]^{++} S O_{4}^{--}$