Observe the following reaction ; A(g) + 3B(g) longrightarrow 2C(g) The rate of this reaction big(-(d [A]/dt) big) is 3 × 10-3 mol L-1 min-1. What is thd value of -(d [B]/dt) in mol L-1 min-1?

Question

Observe the following reaction ; A(g) + 3B(g) longrightarrow 2C(g) The rate of this reaction big(-(d [A]/dt) big) is 3 × 10-3 mol L-1 min-1. What is thd value of -(d [B]/dt) in mol L-1 min-1? (A) 3 × 10-3 (B) 9 × 10-3 (C) 10-3 (D) 1.5 × 10-3

Tardigrade Admin · Accepted Answer

The rationalised rate = -(d [A]/dt) = -(1/3) (d [B]/dt) = (1/2) (d [C]/dt) From this relation we have -(d [B]/dt) = -3 × (d [A]/dt) = -3 × 3 × 10-3 = 9 × 10-3

Q. Observe the following reaction ;
$A (g) + 3 B (g) ⟶ 2 C (g)$
The rate of this reaction $(- \frac{d [ A ]}{d t})$ is
$3 \times 1 0^{- 3} m o l L^{- 1} mi n^{- 1} .$ What is thd value of $- \frac{d [ B ]}{d t}$ in
$m o l L^{- 1} mi n^{- 1}$ ?

$3 \times 1 0^{- 3}$

$9 \times 1 0^{- 3}$

$1 0^{- 3}$

$1.5 \times 1 0^{- 3}$

The rationalised rate =
$- \frac{d [ A ]}{d t} = - \frac{1}{3} \frac{d [ B ]}{d t} = \frac{1}{2} \frac{d [ C ]}{d t}$
From this relation we have
$- \frac{d [ B ]}{d t} = - 3 \times \frac{d [ A ]}{d t}$
$= - 3 \times 3 \times 1 0^{- 3}$
$= 9 \times 1 0^{- 3}$

Q. Observe the following reaction ; A(g)+3B(g)⟶2C(g) The rate of this reaction (−dtd[A]​) is 3×10−3molL−1min−1. What is thd value of −dtd[B]​ in molL−1min−1?

3×10−3

9×10−3

10−3

1.5×10−3