OABC is a current-carrying square loop. An electron is projected from the centre of the loop along with its diagonal AC as shown. The unit vector in the direction of initial acceleration is

Question

OABC is a current-carrying square loop. An electron is projected from the centre of the loop along with its diagonal AC as shown. The unit vector in the direction of initial acceleration is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-xjznt1y1ennl.png" /> (A)  hat k  (B) - (( hat texti + hat textj/√2)) (C) - hat k  (D) ( hati+ hatj/√2)

Tardigrade Admin · Accepted Answer

overset arrow textF = - texte ( overset arrow textV × overset arrow textB) Force will be along BO , or unit vector = - ((. hat texti + hat textj .)/√2)

Q. $O A BC$ is a current-carrying square loop. An electron is projected from the centre of the loop along with its diagonal $A C$ as shown. The unit vector in the direction of initial acceleration is

$\hat{k}$

$- (\frac{i ^ + j ^}{2})$

$- \hat{k}$

$\frac{i ^ + j ^}{2}$

$F \to = - e (V \to \times B \to)$
Force will be along $BO$ , or unit vector $= - \frac{( i ^ + j ^ )}{2}$

Q. OABC is a current-carrying square loop. An electron is projected from the centre of the loop along with its diagonal AC as shown. The unit vector in the direction of initial acceleration is

k^

−(2​i^+j^​​)

−k^

2​i^+j^​​