Tardigrade
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Tardigrade
Question
Chemistry
Number of stereoisomers formed in the given reaction is
Q. Number of stereoisomers formed in the given reaction is
2412
224
AIIMS
AIIMS 2018
Aldehydes Ketones and Carboxylic Acids
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A
2
51%
B
4
25%
C
8
14%
D
6
9%
Solution:
As there is one chiral carbon in the product formed, total number of stereoisomers = 2.