Number of six-digit numbers divisible by 5 that can be formed using the digits 4, 2, 5, 0, 6, 7 each digit to be used exactly once, is

Question

Number of six-digit numbers divisible by 5 that can be formed using the digits 4, 2, 5, 0, 6, 7 each digit to be used exactly once, is (A) 308 (B) 240 (C) 216 (D) none

Tardigrade Admin · Accepted Answer

Total = 6! - 5! = 600 divisible by 5

Q. Number of six-digit numbers divisible by 5 that can be formed using the digits $4, 2, 5, 0, 6, 7$ each digit to be used exactly once, is

308

240

216

none

Total $= 6! - 5! = 600$
divisible by $5$

Q. Number of six-digit numbers divisible by 5 that can be formed using the digits 4,2,5,0,6,7 each digit to be used exactly once, is

308

240

216

none

Total =6!−5!=600 divisible by 5

Q. Number of six-digit numbers divisible by 5 that can be formed using the digits $4, 2, 5, 0, 6, 7$ each digit to be used exactly once, is

Total $= 6! - 5! = 600$
divisible by $5$