Number of possible isomers for the complex [Co(en)2Cl2] Cl will be: (en = ethylenediamine)

Question

Number of possible isomers for the complex [Co(en)2Cl2] Cl will be: (en = ethylenediamine) (A) 3 (B) 4 (C) 2 (D) 1

Tardigrade Admin · Accepted Answer

[Co(en)2 Cl2]Cl Possible isomers - (i) Geometrical isomers (ii) In trans form plane of symmetry present, so trans form is optically inactive but cis is optically active. Total number of stereoisomer = 2+1 =3

Q. Number of possible isomers for the complex $[C o (e n)_{2} C l_{2}] Cl$ will be : (en = ethylenediamine)

3

4

2

1

$[C o (e n)_{2} C l_{2}] Cl$
Possible isomers -
(i) Geometrical isomers
(ii) In trans form plane of symmetry present, so trans form is optically inactive but cis is optically active.
Total number of stereoisomer = 2+1 =3

Q. Number of possible isomers for the complex [Co(en)2​Cl2​]Cl will be : (en = ethylenediamine)

3

4

2

1

[Co(en)2​Cl2​]Cl Possible isomers - (i) Geometrical isomers (ii) In trans form plane of symmetry present, so trans form is optically inactive but cis is optically active. Total number of stereoisomer = 2+1 =3

Q. Number of possible isomers for the complex $[C o (e n)_{2} C l_{2}] Cl$ will be : (en = ethylenediamine)

$[C o (e n)_{2} C l_{2}] Cl$
Possible isomers -
(i) Geometrical isomers
(ii) In trans form plane of symmetry present, so trans form is optically inactive but cis is optically active.
Total number of stereoisomer = 2+1 =3