Number of possible isomers for the complex Co ( en )2 Cl 2 Cl will be: (en= ethylenediamine)

Question

Number of possible isomers for the complex Co ( en )2 Cl 2 Cl will be: (en= ethylenediamine) (A) 3 (B) 4 (C) 2 (D) 1

Tardigrade Admin · Accepted Answer

Number of possible isomers for the complex

C o (e n)_{2} C l_{2} Cl

will be 3 ..
For given complex there are two geometrical isomers cis, trans are possible.Trans form is optically inactive, but cis form is optically active, hence,cis form have two isomers

d & l

.

Q. Number of possible isomers for the complex $C o (e n)_{2} C l_{2} Cl$ will be: $(en= ethylenediamine)

$3$

$4$

$2$

$1$

Number of possible isomers for the complex $C o (e n)_{2} C l_{2} Cl$ will be 3 ..
For given complex there are two geometrical isomers cis, trans are possible.Trans form is optically inactive, but cis form is optically active, hence,cis form have two isomers $d & l$ .

Q. Number of possible isomers for the complex Co(en)2​Cl2​Cl will be: $(en= ethylenediamine)

3

4

2

1

Number of possible isomers for the complex Co(en)2​Cl2​Cl will be 3 .. For given complex there are two geometrical isomers cis, trans are possible.Trans form is optically inactive, but cis form is optically active, hence,cis form have two isomers d&l .

Q. Number of possible isomers for the complex $C o (e n)_{2} C l_{2} Cl$ will be: $(en= ethylenediamine)

$3$

$4$

$2$

$1$

Number of possible isomers for the complex $C o (e n)_{2} C l_{2} Cl$ will be 3 ..
For given complex there are two geometrical isomers cis, trans are possible.Trans form is optically inactive, but cis form is optically active, hence,cis form have two isomers $d & l$ .