Number of oxalic acid molecules in 100 mL of 0.02 N oxalic acid are

Question

Number of oxalic acid molecules in 100 mL of 0.02 N oxalic acid are (A) 6.023 × 1020 (B) 6.023 × 1021 (C) 6.023 × 1022 (D) 6.023 × 1023

Tardigrade Admin · Accepted Answer

0.02 N = 001 M Oxalic acid. The moles of oxalic acid in 100 mL = (0.1 × 100/1000) = 0.001 M 1 mol contains 6.023 × 1023 molecules 10-3 mol = 6 .023 × 1023 × 10-3 = 6. 023 × 1020

Q. Number of oxalic acid molecules in $100 m L$ of $0.02 N$ oxalic acid are

$6.023 \times 1 0^{20}$

$6.023 \times 1 0^{21}$

$6.023 \times 1 0^{22}$

$6.023 \times 1 0^{23}$

$0.02 N = 001 M$ Oxalic acid. The moles of oxalic acid in
$100 m L = \frac{0.1 \times 100}{1000} = 0.001 M$
$1$ mol contains $6.023 \times 1 0^{23}$ molecules
$1 0^{- 3} m o l = 6.023 \times 1 0^{23} \times 1 0^{- 3}$
$= 6.023 \times 1 0^{20}$

Q. Number of oxalic acid molecules in 100mL of 0.02N oxalic acid are

6.023×1020

6.023×1021

6.023×1022

6.023×1023