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Chemistry
Number of oxalic acid molecules in 100 mL of 0.02 N oxalic acid are
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Q. Number of oxalic acid molecules in $100\, mL$ of $0.02\, N$ oxalic acid are
Structure of Atom
A
$6.023 \times 10^{20}$
54%
B
$6.023 \times 10^{21}$
19%
C
$6.023 \times 10^{22}$
12%
D
$6.023 \times 10^{23}$
15%
Solution:
$0.02 \,N = 001 \,M$ Oxalic acid. The moles of oxalic acid in
$100 \,mL = \frac{0.1 \times 100}{1000} = 0.001\,M$
$1$ mol contains $6.023 \times 10^{23}$ molecules
$10^{-3}\, mol = 6 .023 \times 10^{23} \times 10^{-3} $
$= 6. 023 \times 10^{20}$