Question

Number of moles of $K_{2}C{r}_2{O}_7$ reduced by one mole of $S{n}^{2+}$ ions is

• A. 1/3
• B. 3
• C. 1/6
• D. 6

Answer 1

Answer: (A)

$C{r}_2{O}_7^{2-}+14H^{+}+3S{n}^{2+}\to 2C{r}^{3+}+3S{n}^{4+}+7H_{2}O$
Thus, 1 mole of $S{n}^{2+}$ reduces $\frac{1}{3}$ moles of $K_{2}C{r}_2{O}_7$