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Tardigrade
Question
Chemistry
Number of ions present in K4[Fe(CN)6] is
Q. Number of ions present in
K
4
[
F
e
(
CN
)
6
]
is
2052
267
Coordination Compounds
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A
2
13%
B
10
5%
C
3
3%
D
5
79%
Solution:
K
4
[
F
e
(
CN
)
6
]
isacomplexsalt.Onionisationitwilldissociate in
4
K
+
and
[
F
e
(
CN
)
6
]
4
−
ion. Hence, in
K
4
[
F
e
(
CN
)
6
]
five ions are present.