Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Number of integral solutions to the equation x+y+z=21, where x ≥ 1, y ≥ 3, z ≥ 4, is equal to
Q. Number of integral solutions to the equation
x
+
y
+
z
=
21
, where
x
≥
1
,
y
≥
3
,
z
≥
4
, is equal to ___
827
143
JEE Main
JEE Main 2023
Permutations and Combinations
Report Error
Answer:
105
Solution:
15
C
2
=
2
15
×
14
=
105