Number of grams of bromine that will completely react with 5.0 g of pent-1-ene is × 10-2 g. (Atomic mass of Br =80 g / mol ) [Nearest Integer)

Question

Number of grams of bromine that will completely react with 5.0 g of pent-1-ene is × 10-2 g. (Atomic mass of Br =80 g / mol ) [Nearest Integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/707951fa2f47f37c65ef71840c77363f-.png" /> moles of Br 2= moles of C 5 H 10 ⇒ ( W /160)=(5/70) ⇒ W =(5 × 160/70) g =11.428 g =1142.8 × 10-2 g ≈ 1143 × 10-2 g

Q. Number of grams of bromine that will completely react with $5.0 g$ of pent- $1$ -ene is _______ $\times 1 0^{- 2} g$ . (Atomic mass of $B r = 80 g / m o l$ ) [Nearest Integer)

moles of $B r_{2} =$ moles of $C_{5} H_{10}$
$\Rightarrow \frac{W}{160} = \frac{5}{70}$
$\Rightarrow W = \frac{5 \times 160}{70} g$
$= 11.428 g$
$= 1142.8 \times 1 0^{- 2} g \approx 1143 \times 1 0^{- 2} g$

Q. Number of grams of bromine that will completely react with 5.0g of pent-1-ene is _______×10−2g. (Atomic mass of Br=80g/mol ) [Nearest Integer)

moles of Br2​= moles of C5​H10​ ⇒160W​=705​ ⇒W=705×160​g =11.428g =1142.8×10−2g≈1143×10−2g

Q. Number of grams of bromine that will completely react with $5.0 g$ of pent- $1$ -ene is _______ $\times 1 0^{- 2} g$ . (Atomic mass of $B r = 80 g / m o l$ ) [Nearest Integer)

moles of $B r_{2} =$ moles of $C_{5} H_{10}$
$\Rightarrow \frac{W}{160} = \frac{5}{70}$
$\Rightarrow W = \frac{5 \times 160}{70} g$
$= 11.428 g$
$= 1142.8 \times 1 0^{- 2} g \approx 1143 \times 1 0^{- 2} g$