Number of terms in (1+x)2009=2010....(1) + additional terms in (1+x2)2008=x2010+x2012+…….+x4016=1004...(2) + additional terms in (1+x3)2007=x2010+x2013+……..+x4014+….+x6021=1338...(3) −( common to 2 and 3)=x2010+x2016+…...+x4014)=335 Hence total =2010+1004+1338−335 =4352−335=4017