Number of crystal systems having only 24 types of bravais lattices =x, number of crystal system having at least two interfacial angles equal = y and number of crystal systems having all the three edge lengths equal =z. Then find the value of x × y × z.

Question

Number of crystal systems having only 24 types of bravais lattices =x, number of crystal system having at least two interfacial angles equal = y and number of crystal systems having all the three edge lengths equal =z. Then find the value of x × y × z. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

x=2 (Tetragonal, Monoclinic) y=6 (except triclinic all the bravis lattices) z =2 (Cubic, Rhombohedral) xyz =(2)(6)(2)=24.00

Q. Number of crystal systems having only $24$ types of bravais lattices $= x$ , number of crystal system having at least two interfacial angles equal $= y$ and number of crystal systems having all the three edge lengths equal $= z$ . Then find the value of $x \times y \times z$ .

$x = 2$ (Tetragonal, Monoclinic)
$y = 6$ (except triclinic all the bravis lattices)
$z = 2$ (Cubic, Rhombohedral)
$x yz = (2) (6) (2) = 24.00$

Q. Number of crystal systems having only 24 types of bravais lattices =x, number of crystal system having at least two interfacial angles equal =y and number of crystal systems having all the three edge lengths equal =z. Then find the value of x×y×z.

x=2 (Tetragonal, Monoclinic) y=6 (except triclinic all the bravis lattices) z=2 (Cubic, Rhombohedral) xyz=(2)(6)(2)=24.00

Q. Number of crystal systems having only $24$ types of bravais lattices $= x$ , number of crystal system having at least two interfacial angles equal $= y$ and number of crystal systems having all the three edge lengths equal $= z$ . Then find the value of $x \times y \times z$ .

$x = 2$ (Tetragonal, Monoclinic)
$y = 6$ (except triclinic all the bravis lattices)
$z = 2$ (Cubic, Rhombohedral)
$x yz = (2) (6) (2) = 24.00$