Number of common tangents of the circles (x+2)2+(y-2)2=49 and (x-2)2+(y+1)2=4 is:

Question

Number of common tangents of the circles (x+2)2+(y-2)2=49 and (x-2)2+(y+1)2=4 is: (A) 0 (B) 1 (C) 2 (D) 3

Tardigrade Admin · Accepted Answer

C1 C2=5, r1=7, r2=2 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/1a0a3403a9336766c6b03a215e30f971-.png" /> C1 C2=|r1-r2| ⇒ one common tangent

Q. Number of common tangents of the circles $(x + 2)^{2} + (y - 2)^{2} = 49$ and $(x - 2)^{2} + (y + 1)^{2} = 4$ is:

0

1

2

3

$C_{1} C_{2} = 5, r_{1} = 7, r_{2} = 2$

$C_{1} C_{2} = ∣ r_{1} - r_{2} ∣ \Rightarrow$ one common tangent

Q. Number of common tangents of the circles (x+2)2+(y−2)2=49 and (x−2)2+(y+1)2=4 is:

0

1

2

3

C1​C2​=5,r1​=7,r2​=2 C1​C2​=∣r1​−r2​∣⇒ one common tangent

Q. Number of common tangents of the circles $(x + 2)^{2} + (y - 2)^{2} = 49$ and $(x - 2)^{2} + (y + 1)^{2} = 4$ is:

$C_{1} C_{2} = 5, r_{1} = 7, r_{2} = 2$

$C_{1} C_{2} = ∣ r_{1} - r_{2} ∣ \Rightarrow$ one common tangent