Question

Number of atoms in $558.5gFe\left(at.wt.55.85\right)$ is:

• A. Twice that in $60g$ carbon
• B. $6.023\times 10^{22}$
• C. Half in $8gHe$
• D. $558.5\times 6.023\times 10^{23}$

Answer 1

Answer: (A)

Moles of $Fe=\frac{558.5}{55.85}=10$
Moles of $C=\frac{60}{12}=5$