Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
Number of acyclic structural isomers of the compound having the molecular formula C4H10O is
Q. Number of acyclic structural isomers of the compound having the molecular formula
C
4
H
10
O
is
1965
173
KEAM
KEAM 2016
Alcohols Phenols and Ethers
Report Error
A
4
10%
B
5
8%
C
6
20%
D
7
53%
E
3
53%
Solution:
Total number of acyclic structural isomers
=
7
Due to
−
O
H
group (4)
1.
C
H
3
C
H
2
−
C
H
2
−
C
H
2
−
O
H
2.
C
H
3
−
C
H
2
−
O
H
∣
C
H
−
C
H
3
O
H
3.
C
H
3
−
C
H
3
∣
C
H
−
C
H
2
−
O
H
4.
C
H
3
−
C
H
3
∣
C
∣
C
H
3
−
O
H
Due to
−
O
−
group, i.e. ethers
(
3
)
.
1.
C
H
3
−
O
−
C
H
2
−
C
H
2
−
C
H
3
2.
C
H
3
−
C
H
2
−
O
−
C
H
2
−
C
H
3
3.
Total
=
4
+
3
=
7
