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Tardigrade
Question
Chemistry
Number of acyclic structural isomers of the compound having the molecular formula C4H10O is
Q. Number of acyclic structural isomers of the compound having the molecular formula
C
4
H
10
O
is
1922
170
KEAM
KEAM 2016
Alcohols Phenols and Ethers
Report Error
A
4
10%
B
5
8%
C
6
20%
D
7
53%
E
3
53%
Solution:
Total number of acyclic structural isomers
=
7
Due to
−
O
H
group (4)
1.
C
H
3
C
H
2
−
C
H
2
−
C
H
2
−
O
H
2.
C
H
3
−
C
H
2
−
O
H
∣
C
H
−
C
H
3
O
H
3.
C
H
3
−
C
H
3
∣
C
H
−
C
H
2
−
O
H
4.
C
H
3
−
C
H
3
∣
C
∣
C
H
3
−
O
H
Due to
−
O
−
group, i.e. ethers
(
3
)
.
1.
C
H
3
−
O
−
C
H
2
−
C
H
2
−
C
H
3
2.
C
H
3
−
C
H
2
−
O
−
C
H
2
−
C
H
3
3.
Total
=
4
+
3
=
7
