Nuclear reactor in which U-235 is used as fuel. Uses 2 kg of U-235 in 30 days. Then, power output of the reactor will be (given energy released per fission =185 M eV )

Question

Nuclear reactor in which U-235 is used as fuel. Uses 2 kg of U-235 in 30 days. Then, power output of the reactor will be (given energy released per fission =185 M eV ) (A) 43.5 MW (B) 58.5 MW (C) 69.6 MW (D) 73.1 MW

Tardigrade Admin · Accepted Answer

Number of atoms in 2 kg of uranium =(6.02 × 1023/235) × 2000 =5.12 × 1024 Therefore, energy obtained from these atoms =5.12 × 1024 × 185 MeV =5.12 × 1024 × 185 × 106 eV Energy obtained per second =(5.12 × 1024 × 185 × 106 × 16 × 10-19/30 × 24 × 60 × 60) Solving the above expression =5847 × 106 W ≅ 58.5 MW

Q. Nuclear reactor in which U−235 is used as fuel. Uses 2kg of U−235 in 30 days. Then, power output of the reactor will be (given energy released per fission =185MeV )

43.5 MW

58.5 MW

69.6 MW

73.1 MW

Number of atoms in 2kg of uranium =2356.02×1023​×2000 =5.12×1024 Therefore, energy obtained from these atoms =5.12×1024×185MeV =5.12×1024×185×106eV Energy obtained per second =30×24×60×605.12×1024×185×106×16×10−19​ Solving the above expression =5847×106W≅58.5MW

Q. Nuclear reactor in which $U - 235$ is used as fuel. Uses $2 k g$ of $U - 235$ in $30$ days. Then, power output of the reactor will be (given energy released per fission $= 185 M e V$ )