Notation form of (a+b)n is

Question

Notation form of (a+b)n is (A)  displaystyle∑ k =0 n n C k a n + k b k  (B)  displaystyle∑k=0n n Ck an-k bk (C)  displaystyle∑ k =0 n C k b n + k a k  (D) None of these

Tardigrade Admin · Accepted Answer

The notation ∑ k =0 n n C k a n - k b k stands for n C 0 a n b 0+ n C 1 a n -1 b 1+ ldots+ n C r a n - r b r + ldots+ n C n a n - n b n where, b0=1=an-n Hence, the notation form of (a+b)n is (a+b)n= displaystyle∑k=0n n Ck an-k bk

Q. Notation form of $(a + b)^{n}$ is

$k = 0 \sum n^{n} C_{k} a^{n + k} b^{k}$

$k = 0 \sum n^{n} C_{k} a^{n - k} b^{k}$

$k = 0 \sum n C_{k} b^{n + k} a^{k}$

None of these

Q. Notation form of (a+b)n is

k=0∑n​nCk​an+kbk

k=0∑n​nCk​an−kbk

k=0∑n​Ck​bn+kak

None of these

The notation ∑k=0n​nCk​an−kbk stands for nC0​anb0+nC1​an−1b1+…+nCr​an−rbr+…+nCn​an−nbn where, b0=1=an−n Hence, the notation form of (a+b)n is (a+b)n=k=0∑n​nCk​an−kbk

Q. Notation form of $(a + b)^{n}$ is

$k = 0 \sum n^{n} C_{k} a^{n + k} b^{k}$

$k = 0 \sum n^{n} C_{k} a^{n - k} b^{k}$

$k = 0 \sum n C_{k} b^{n + k} a^{k}$