Not considering the electron spin, the degeneracy of second excited state is 9, while the degeneracy of second excited state of H - is-

Question

Not considering the electron spin, the degeneracy of second excited state is 9, while the degeneracy of second excited state of H - is- (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

H -(2):-1 s 2 It's a multielectron specie, first excited state will be 2s 2 text nd excited state will be 2 p. Degeneracy of 2s is 1 Degeneracy of 2p will be 3

Q. Not considering the electron spin, the degeneracy of second excited state is $9,$ while the degeneracy of second excited state of $H^{-}$ is-

1

2

3

4

$H^{-} (2) : - 1 s^{2}$

It's a multielectron specie, first excited state will be $2 s$ & $2^{nd}$ excited state will be 2 p. Degeneracy of $2 s$ is $1$ Degeneracy of $2 p$ will be $3$

Q. Not considering the electron spin, the degeneracy of second excited state is 9, while the degeneracy of second excited state of H− is-

1

2

3

4

H−(2):−1s2 It's a multielectron specie, first excited state will be 2s & 2nd excited state will be 2 p. Degeneracy of 2s is 1 Degeneracy of 2p will be 3

Q. Not considering the electron spin, the degeneracy of second excited state is $9,$ while the degeneracy of second excited state of $H^{-}$ is-

$H^{-} (2) : - 1 s^{2}$

It's a multielectron specie, first excited state will be $2 s$ & $2^{nd}$ excited state will be 2 p. Degeneracy of $2 s$ is $1$ Degeneracy of $2 p$ will be $3$