Nitrobenzene on reduction using zinc in alkaline medium gives hydrazobenzene.

Hydrazobenzene $(X)$ contains $27 σ$ and $6 π$ bonds.

Question

Nitrobenzene on reduction using zinc in alkaline medium results in X. The number of sigma (σ) and pi (π) bonds in X is (A) 24 σ, 7 π (B) 24 σ, 6 π (C) 27 σ, 7 π (D) 27 σ, 6 π

Tardigrade Admin · Accepted Answer

Nitrobenzene on reduction using zinc in alkaline medium gives hydrazobenzene. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/8431b3f5aa9a1c47469da7ee0e339c27-.png" /> Hydrazobenzene (X) contains 27 σ and 6 π bonds.

Q. Nitrobenzene on reduction using zinc in alkaline medium results in $X$ . The number of sigma $(σ)$ and pi $(π)$ bonds in $X$ is

$24 σ, 7 π$

$24 σ, 6 π$

$27 σ, 7 π$

$27 σ, 6 π$

Nitrobenzene on reduction using zinc in alkaline medium gives hydrazobenzene.

Hydrazobenzene $(X)$ contains $27 σ$ and $6 π$ bonds.

Q. Nitrobenzene on reduction using zinc in alkaline medium results in X. The number of sigma (σ) and pi (π) bonds in X is

24σ,7π

24σ,6π

27σ,7π

27σ,6π

Nitrobenzene on reduction using zinc in alkaline medium gives hydrazobenzene. Hydrazobenzene (X) contains 27σ and 6π bonds.

Q. Nitrobenzene on reduction using zinc in alkaline medium results in $X$ . The number of sigma $(σ)$ and pi $(π)$ bonds in $X$ is

$24 σ, 7 π$

$24 σ, 6 π$

$27 σ, 7 π$

$27 σ, 6 π$

Nitrobenzene on reduction using zinc in alkaline medium gives hydrazobenzene.

Hydrazobenzene $(X)$ contains $27 σ$ and $6 π$ bonds.