Nitration of aniline in strong acidic medium also gives m-nitroaniline because

Question

Nitration of aniline in strong acidic medium also gives m-nitroaniline because (A) In acidic (strong) medium aniline is present as anilinium ion. (B) In spite of substituents nitro group always goes to only m-position. (C) In absence of substituents nitro group always goes to m-position. (D) In electrophilic substitution reactions amino group is meta directive.

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/57e297fa733ac48e2f14583b34a3ad15-.png" /> - overset⊕N H3 is m-directing, hence besides para (51 %) and ortho (2 %), meta product (47 %) is also formed in significant yield.

Q. Nitration of aniline in strong acidic medium also gives m-nitroaniline because

In acidic (strong) medium aniline is present as anilinium ion.

In spite of substituents nitro group always goes to only m-position.

In absence of substituents nitro group always goes to m-position.

In electrophilic substitution reactions amino group is meta directive.

$- N \oplus H_{3}$ is m-directing, hence besides para

$(51%)$ and ortho $(2%)$ , meta product $(47%)$ is also formed in significant yield.

Q. Nitration of aniline in strong acidic medium also gives m-nitroaniline because

In acidic (strong) medium aniline is present as anilinium ion.

In spite of substituents nitro group always goes to only m-position.

In absence of substituents nitro group always goes to m-position.

In electrophilic substitution reactions amino group is meta directive.

−N⊕H3​ is m-directing, hence besides para (51%) and ortho (2%), meta product (47%) is also formed in significant yield.

$- N \oplus H_{3}$ is m-directing, hence besides para

$(51%)$ and ortho $(2%)$ , meta product $(47%)$ is also formed in significant yield.