Nickel (Z = 28) combines with a uninegative monodentate ligand X- to form a paramagnetic complex [NiX4]2-. The number of unpaired electron(s) in the nickel and geometry of this complex ion are respectively:

Question

Nickel (Z = 28) combines with a uninegative monodentate ligand X- to form a paramagnetic complex [NiX4]2-. The number of unpaired electron(s) in the nickel and geometry of this complex ion are respectively: (A) one, tetrahedral (B) two, tetrahedral (C) one, square planar (D) two, square planar

Tardigrade Admin · Accepted Answer

Nickel has two unpaired electrons and geometry is tetrahedral due to sp3 hybridisation.

Q. Nickel (Z = 28) combines with a uninegative monodentate ligand $X^{-}$ to form a paramagnetic complex $[N i X_{4}]^{2 -}$ . The number of unpaired electron(s) in the nickel and geometry of this complex ion are respectively:

one, tetrahedral

two, tetrahedral

one, square planar

two, square planar

Nickel has two unpaired electrons and geometry is tetrahedral due to $s p^{3}$ hybridisation.

Q. Nickel (Z = 28) combines with a uninegative monodentate ligand X− to form a paramagnetic complex [NiX4​]2−. The number of unpaired electron(s) in the nickel and geometry of this complex ion are respectively: