NH 3 is produced according to the following reaction: N 2( g )+3 H 2( g ) arrow 2 NH 3( g ) In an experiment 0.25 mol of NH 3 is formed when 0.5 mol of N 2 is reacted with 0.5 mol of H 2. What is % yield?

Question

NH 3 is produced according to the following reaction: N 2( g )+3 H 2( g ) arrow 2 NH 3( g ) In an experiment 0.25 mol of NH 3 is formed when 0.5 mol of N 2 is reacted with 0.5 mol of H 2. What is % yield? (A) 75 % (B) 50 % (C) 33 % (D) 25 %

Tardigrade Admin · Accepted Answer

% yield =( text produced mol of NH 3 × 100/ text max. possible produced mole of NH 3) =(0.25/0.5 × (2)3) × 100=75 %

Q. $N H_{3}$ is produced according to the following reaction:
$N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)$
In an experiment $0.25 m o l$ of $N H_{3}$ is formed when $0.5 m o l$ of $N_{2}$ is reacted with $0.5 m o l$ of $H_{2}$ . What is $%$ yield?

$75%$

$50%$

$33%$

$25%$

$%$ yield $= \frac{produced mol of N H _{3} \times 100}{max. possible produced mole of N H _{3}}$
$= \frac{0.25}{0.5 \times \frac{2}{3}} \times 100 = 75%$

Q. NH3​ is produced according to the following reaction: N2​(g)+3H2​(g)→2NH3​(g) In an experiment 0.25mol of NH3​ is formed when 0.5mol of N2​ is reacted with 0.5mol of H2​. What is % yield?

75%

50%

33%

25%