Question

Neopentyl bromide, undergoes dehydrohalogenation to give alkenes even though it has no $\text{β}-\text{H}$ . This is due to

• A. ${\text{E}}_{\text{2}}$ mechanism
• B. Rearrangement of carbocations by ${\text{E}}_{\text{1}}$ mechanism
• C. ${\text{E}}_{\text{1}}\text{cB}$ mechanism
• D. ${\text{E}}_{\text{4}}$ mechanism

Answer 1

Answer: (B)

Neopentyl bromide give a carbocation as intermediate which undergo for rearrangement and show ${\text{E}}_{\text{1}}$ mechanism (even though it has no $\text{β}-\text{H}$ atom).

Thus Rearrangement of carbocations by ${\text{E}}_{\text{1}}$ mechanism is the correct option.